- **How do I...?**
(*http://www.alice.org/community/forumdisplay.php?f=16*)

- - **knowing the size of an object?**
(*http://www.alice.org/community/showthread.php?t=6060*)

[QUOTE=David B;32089]I should just make a health bar model, and create a standard method within it and upload it to the forums so people can use it and never worry about making health bars again![/QUOTE]
well i finally perfected the health bar im using, it turned out pretty awesome, im going to reupload my game tomorrow, becuase the one i have on now has a few things that are just wasted memory space |

[QUOTE=debussybunny563;32076][SIZE="2"]I'm interested in your opinion...
Do you think 0.999.... is equal to 1?[/SIZE][/QUOTE] I think the point here is that the "..."'s represent a iteration of the digit "9" indefinitely. Therefore you meant .999999999 with an infinite number of 9's afterward, right? So using the algebra I know to convert repeating decimals into fractions: x = 0.999... //Set x to the decimal: 10x = 9.999... //Multiply by ten on both sides. 10x - x = 9.999... - 0.999... //Used the information above for this expression 9x = 9 //Simplify (since the repeating decimal part is the same for both 9.999... and 0.999..., they cancel out) [B]x = 1 [/B] //Divide by nine on both sides. Therefore 0.999... is equal to 1. |

[SIZE="2"][QUOTE=reuben2011;32096]I think the point here is that the "..."'s represent a iteration of the digit "9" indefinitely. Therefore you meant .999999999 with an infinite number of 9's afterward, right? So using the algebra I know to convert repeating decimals into fractions:
x = 0.999... //Set x to the decimal: 10x = 9.999... //Multiply by ten on both sides. 10x - x = 9.999... - 0.999... //Used the information above for this expression 9x = 9 //Simplify (since the repeating decimal part is the same for both 9.999... and 0.999..., they cancel out) [B]x = 1 [/B] //Divide by nine on both sides. Therefore 0.999... is equal to 1.[/QUOTE] That's one of the algebraic methods mathematicians use to prove it. There's also the idea that 0.9 repeating gets closer and closer to 1, but never quite reaches it.[/SIZE] |

[QUOTE=debussybunny563;32114][SIZE="2"]
That's one of the algebraic methods mathematicians use to prove it. There's also the idea that 0.9 repeating gets closer and closer to 1, but never quite reaches it.[/SIZE][/QUOTE] if it's a limit, you use the derivative of whatever function you are using and figure out the number in which this case, if it is .999.... then you could say the limit is (-infinty,1)u(1,infinity). and to find the function you started out with you would have to do the antiderivative of .999 which would go to .999x. so like i said before, all depends on the application of the number |

All times are GMT -5. The time now is 08:45 AM. |

Copyright ©2019, Carnegie Mellon University

Alice 2.x © 1999-2012, Alice 3.x © 2008-2012, Carnegie Mellon University. All rights reserved.