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-   -   knowing the size of an object? (http://www.alice.org/community/showthread.php?t=6060)

 sfunk 03-10-2011 09:11 PM

[QUOTE=David B;32089]I should just make a health bar model, and create a standard method within it and upload it to the forums so people can use it and never worry about making health bars again![/QUOTE]

well i finally perfected the health bar im using, it turned out pretty awesome, im going to reupload my game tomorrow, becuase the one i have on now has a few things that are just wasted memory space

 reuben2011 03-11-2011 12:04 AM

Do you think 0.999.... is equal to 1?[/SIZE][/QUOTE]

I think the point here is that the "..."'s represent a iteration of the digit "9" indefinitely. Therefore you meant .999999999 with an infinite number of 9's afterward, right? So using the algebra I know to convert repeating decimals into fractions:

x = 0.999... //Set x to the decimal:
10x = 9.999... //Multiply by ten on both sides.

10x - x = 9.999... - 0.999... //Used the information above for this
expression

9x = 9 //Simplify (since the repeating decimal part is
the same for both 9.999... and 0.999..., they
cancel out)

[B]x = 1 [/B] //Divide by nine on both sides.

Therefore 0.999... is equal to 1.

 debussybunny563 03-11-2011 03:03 PM

[SIZE="2"][QUOTE=reuben2011;32096]I think the point here is that the "..."'s represent a iteration of the digit "9" indefinitely. Therefore you meant .999999999 with an infinite number of 9's afterward, right? So using the algebra I know to convert repeating decimals into fractions:

x = 0.999... //Set x to the decimal:
10x = 9.999... //Multiply by ten on both sides.

10x - x = 9.999... - 0.999... //Used the information above for this
expression

9x = 9 //Simplify (since the repeating decimal part is
the same for both 9.999... and 0.999..., they
cancel out)

[B]x = 1 [/B] //Divide by nine on both sides.

Therefore 0.999... is equal to 1.[/QUOTE]

That's one of the algebraic methods mathematicians use to prove it.

There's also the idea that 0.9 repeating gets closer and closer to 1, but never quite reaches it.[/SIZE]

 sfunk 03-11-2011 03:56 PM

[QUOTE=debussybunny563;32114][SIZE="2"]

That's one of the algebraic methods mathematicians use to prove it.

There's also the idea that 0.9 repeating gets closer and closer to 1, but never quite reaches it.[/SIZE][/QUOTE]

if it's a limit, you use the derivative of whatever function you are using and figure out the number in which this case, if it is .999.... then you could say the limit is (-infinty,1)u(1,infinity). and to find the function you started out with you would have to do the antiderivative of .999 which would go to .999x. so like i said before, all depends on the application of the number

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