Alice Community knowing the size of an object?
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sfunk
Senior Member

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Posts: 1,112
Join Date: Mar 2011
Location: I don't know
03-10-2011, 09:11 PM

Quote:
 Originally Posted by David B I should just make a health bar model, and create a standard method within it and upload it to the forums so people can use it and never worry about making health bars again!
well i finally perfected the health bar im using, it turned out pretty awesome, im going to reupload my game tomorrow, becuase the one i have on now has a few things that are just wasted memory space

reuben2011
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Posts: 489
Join Date: Sep 2009
Location: Hawaii
03-11-2011, 12:04 AM

Quote:
 Originally Posted by debussybunny563 I'm interested in your opinion... Do you think 0.999.... is equal to 1?
I think the point here is that the "..."'s represent a iteration of the digit "9" indefinitely. Therefore you meant .999999999 with an infinite number of 9's afterward, right? So using the algebra I know to convert repeating decimals into fractions:

x = 0.999... //Set x to the decimal:
10x = 9.999... //Multiply by ten on both sides.

10x - x = 9.999... - 0.999... //Used the information above for this
expression

9x = 9 //Simplify (since the repeating decimal part is
the same for both 9.999... and 0.999..., they
cancel out)

x = 1 //Divide by nine on both sides.

Therefore 0.999... is equal to 1.

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debussybunny563
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03-11-2011, 03:03 PM

Quote:
 Originally Posted by reuben2011 I think the point here is that the "..."'s represent a iteration of the digit "9" indefinitely. Therefore you meant .999999999 with an infinite number of 9's afterward, right? So using the algebra I know to convert repeating decimals into fractions: x = 0.999... //Set x to the decimal: 10x = 9.999... //Multiply by ten on both sides. 10x - x = 9.999... - 0.999... //Used the information above for this expression 9x = 9 //Simplify (since the repeating decimal part is the same for both 9.999... and 0.999..., they cancel out) x = 1 //Divide by nine on both sides. Therefore 0.999... is equal to 1.
That's one of the algebraic methods mathematicians use to prove it.

There's also the idea that 0.9 repeating gets closer and closer to 1, but never quite reaches it.

Last edited by debussybunny563; 12-21-2012 at 12:00 AM.

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I have been dead for quite some time now; not much hope for resurrection.

sfunk
Senior Member

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Posts: 1,112
Join Date: Mar 2011
Location: I don't know
03-11-2011, 03:56 PM

Quote:
 Originally Posted by debussybunny563 That's one of the algebraic methods mathematicians use to prove it. There's also the idea that 0.9 repeating gets closer and closer to 1, but never quite reaches it.
if it's a limit, you use the derivative of whatever function you are using and figure out the number in which this case, if it is .999.... then you could say the limit is (-infinty,1)u(1,infinity). and to find the function you started out with you would have to do the antiderivative of .999 which would go to .999x. so like i said before, all depends on the application of the number

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