**CTET/ UPTET Exam Practice Mathematics Questions**

**Q1. Which one of the following is the correct sequence in respect of the Roman numerals: C, D, L and M?**

(a) C > D > L > M

(b) M > L > D > C

(c) M > D > C > L

(d) L > C > D > M

**Q2. If the numbers from 1 to 24, which are divisible by 2 are arranged in descending order, which number will be at the 8th place from the bottom?**

(a) 10

(b) 12

(c) 16

(d) 18

**Q3. 2 – 2 + 2 – 2 + ………. 101 terms = ?**

(a) –2

(b) 0

(c) 2

(d) None of these

**Q4. 98th term of the infinite series 1, 2, 3, 4, 1, 2, 3, 4, 1, 2, …….. is**

(a) 1

(b) 2

(c) 3

(d) 4

**Q5. If x, y, z be the digits of a number beginning from the left, the number is**

(a) xyz

(b) x + 10y + 100z

(c) 10x + y + 100z

(d) 100x + 10y + z

**Q6. If x, y, z and w be the digits of a number beginning from the left, the number is**

(a) xyzw

(b) wzyx

(c) x + 10y + 100z + 1000w

(d) 10³x + 10²y + 10z + w

**Q7. If n and p are both odd numbers, which of the following is an even number?**

(a) n + p

(b) n + p + 1

(c) np + 2

(d) np

**Q8. For the integer n, if n³ is odd, then which of the following statements are true?I. n is odd.II. n² is odd.III. n² is even.**

(a) I only

(b) II only

(c) I and II only

(d) I and III only

**Q9. If (n – 1) is an odd number, what are the two other odd numbers nearest to it?**

(a) n, n – 1

(b) n, n – 2

(c) n – 3, n + 1

(d) n – 3, n + 5

**Q10. Which of the following is always odd?**

(a) Sum of two odd numbers

(b) Difference of two odd numbers

(c) Product of two odd numbers

(d) None of these

**Solutions**

S1. Ans.(c)

Sol. We have, M = 1000 ; D = 500 ; C = 100 and L = 50.

∴ M > D > C > L is the correct sequence.

S2. Ans.(c)

Sol. These numbers are 24, 22, 20, 18, 16, 14, 12, 10, 8, 6, 4, 2. 8th number from the bottom is 16.

S3. Ans.(c)

Sol. Clearly, the given series is such that the sum of any odd number of terms is 2 while that of any even number of terms is 0. Thus, sum of 101 terms is 2.

S5. Ans.(d)

Sol. Let the hundred’s, ten’s and one’s digits be x, y and z respectively.

Then, the given number is 100 x + 10 y + z.

S6. Ans.(d)

Sol. Let the thousand’s, ten’s hundred’s, ten’s and one’s digits be x, y, z, w respectively.

Then, the number is 1000 x + 100 y + 10 z + w = 10³ x + 10² y + 10 z + w.

S7. Ans.(a)

Sol. We know that the sum of two odd numbers is even.

∴ (n is odd, p is odd) ⇒ (n + p) is even.

S8. Ans.(c)

Sol. n³ is odd ⇒ n is odd and n² is odd.

∴ I and II are true.

S9. Ans.(c)

Sol. (n – 1) is odd ⇒ (n – 1) – 2 and (n – 1) + 2 are odd ⇒ (n – 3) and (n + 1) are odd.

S10. Ans.(c)

Sol. The product of two odd numbers is always odd.

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